In the hands of someone who steals or does not return borrowed books, the book should turn into a predatory snake. She should paralyze and cripple all his limbs. With a loud scream should beg for mercy, and let not alleviate suffering, until you reach the decomposition. In his guts let them gnaw bookworm worm death that never dies. And when it arrives the last sentence, let him devour hellfire forever.

A) oxides: If, for example octave sodium oxide formula will certainly octave contain Na - sodium and O - oxygen (hear the title) in the carbon oxygen is always second! The formula therefore is NaO, but what oxidation number? Without those you can not, you can not get a formula so that there'll octave write two brand elements - that would be too easy! Up to O must write oxidation number, octave which is always -2 oxides (oxidation octave numbers are written Rimsky). According terminals (NY monoxide, dioxide, ICIT, ičný ečný, AC, sure, ICEL) have odvodíš that the oxidation number for Na is +1. Now I need to quantify. Always vynásobíš numbers that are one above the other in one brand element. Both results among themselves subtract. Now, would you based 1-2 = first But you always have to go 0! This result docílíš so that instead of 1 give two. In the formula, you do so that you write 2 subscript u Na (oxidation number can not be changed if you have typed the name!) And Now the formula is complete, because Ti is based on 2-2 = 0! If you enter a formula Al 2 O 3 gotta vice versa. The title will certainly oxide .... Oxygen has always oxides oxidation number of -2. Write it to oxygen! Now comes Ti: 2-6 = -4. Ty, but you want is = 0. Here it docílíš so that 2 give 6. In formula thus you add Al in the oxidation number of 3 (when the specified pattern can not be changed subscripts, but the oxidation number!). So the name of the carbon dioxide + aluminum (dioxide, because they came out of aluminum oxidation number of +3). So the result is: alumina!

D) acids: divided into oxygen and without oxygen. Oxygen Free: you know by the fact that at the end of the name is hydrogen. In the case of hydrogen sulfide acid: first acid in the formula is always H. When the oxygen-free, followed by a further element octave - the sulfur - S. We thus HS. Now oxidation number: H is usually +1 (in the case of acids each) and S as a sulfide -2. In an oxygen-free acid is very simple: if the second element has -1 so that the registration number of the affirmative as a subscript to hydrogen H. Thus, hydrogen sulphide acid has the formula H 2 S.Pokud is specified pattern, reverse the removal procedure, but beware that can only mněnit oxidation numbers! If oxygen acid: e.g. nitric acid will certainly formula H (hydrogen), N (nitrogen) and O (oxygen-it is after all oxygen acid!). Hydrogen is always the first place and oxygen octave is always the last - remaining element is thus in the midst. So we have: HNO. Now oxidation number: H Acid has always +1 and -2 always oxygen. The intermediate element has an oxidation number by name (terminals!), In this case the nitrogen at an oxidation number of +5. The pattern imaginary line to divide positive and negative parts. Multiply the number above and tell him, and subtract what I came out. They come here thus: 1 + 5-2 = 4th Ty, but again you need the result 0. If the central element have an oxidation number octave is even, let the hydrogen subscript 2 to Ti on the positive side created together even number. octave Then put the oxygen subscript so that Ti result came 0. In this case, the third Result: HNO 3. Where a pattern, reverse octave the removal procedure, but beware that you can only mněnit oxidation numbers! Perhaps you understand. A little protrénuj it at home! Narsis

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