Saturday, October 26, 2013

Bra-bantenor


Today, let's consider the two-step titration discoloration region of the titration curve appears in two places. Routine testing is over, visitors of a blog has decreased considerably. Ne is a pity. People who have a habit that you learn to see the blog not only before the test, will be a sure winner. Now it's time to take a problem. Where it takes a mixed aqueous solution of 20mL and sodium carbonate sodium hydroxide unknown concentration was titrated with hydrochloric acid 1.0mol / L, neutralization titration membrane curve as above were obtained. Sodium carbonate and sodium hydroxide membrane contained in the mixed solution of 20mL something mol, respectively. In place of the transition interval) (the first answer) first neutralization point, NaOH + HCl NaCl + H 2 O - in a mixed solution of this 3 + NaCl over Na 2 CO 3 + HCl NaHCO, membrane NaOH is Xmol , Na 2 CO 3 is a Ymol, it becomes HCl = X + Ymol that is dropped into the mixed solution. In (discoloration area come out for the second time) second point of neutralization HCl = 0.10mol / L 15/1000L = X + Ymol, by the way 2 O + CO 2 over NaHCO 3 + HCl NaCl + H, the equation HCl and Na 2 CO 3 and NaHCO 3 as well, because everyone is a Ymol, HCl and NaHCO 3 of is Ymol. Therefore, HCl that was used in the second membrane neutralization point equation HCl = 0.10 Y = 0.050mol (answer), the first point of neutralization by solving (20-15) membrane / 1000L this Ymol = 1.0mol / L by substituting the Y = 0.050 to mol / L 15/1000L = X + Ymol, thank you X = 0.0050mol (answer) X = 0.010mol / L, Y = 0.0050mol / L and (answer) Pochitto.
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